Item 8 Anchor Papers    

HSA 2008 Algebra/Data Analysis Item 8

CID
CID48f10ffd279ff957d2fe9be229c92a89
itemNum
8
initialLetter
itemType
ECR
itemAnswerKey
N/A
itemMaxScorePoints
4
origNum
12

Ichiro plans to spend no more than a total of $60 for both lunch and dinner each day during his vacation.

Complete the following in the Answer Book:

  • Write an inequality that models this relationship. Let x represent the amount, in dollars, that Ichiro spends on lunch. Let y represent the amount, in dollars, that Ichiro spends on dinner.
  • Graph the inequality on the grid provided in the Answer Book.
  • On Thursday, Ichiro spent exactly $60 on lunch and dinner. He spent three times as much on dinner as he spent on lunch. How much did Ichiro spend on lunch? How much did Ichiro spend on dinner? Use mathematics to explain how you determined your answers. Use words, symbols, or both in your explanations.

Score Level 1 Anchor Paper

 

This response indicates little application of a reasonable strategy. The representation in the form of an inequality is correct (y+x≤60). The student provides no response to the second or third parts of the question. This response demonstrates a minimal understanding and analysis of the problem.

image of student response

Score Level 1 Anchor Paper

 

This response indicates little application of a reasonable strategy. The representation in the form of an equation, rather than an inequality, is relevant (x+y=60). The student provides no response to the second part of the question. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. However, explanations are not provided. This response demonstrates a minimal understanding and analysis of the problem.

image of student response

Score Level 2 Anchor Paper

 

This response indicates application of an incomplete strategy. The representation in the form of an inequality is correct (x+y≤60). While the student assigns the axes on the grid as x and y, the inequality is not graphed. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. The explanation supports the solution (dividing 60 by 3, subtracting 5, recieving in answer of 15, multiplying 15 by 4, checking my answer to make sure it was correct. Then I multiplied 15x3 and got 45 then adding 45+15 and got $60; 45/3 is 15). This response demonstrates a conceptual understanding and analysis of the problem.

image of student response

Score Level 2 Anchor Paper

 

This response indicates application of an incomplete strategy. The representation in the form of an inequality is correct (x+y≤60). Although the student assigned scales and labels on the grid, the inequality is not graphed. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. The student provides a justification, rather than an explanation (I added 15 + 15 x 3 and got 60). This response demonstrates a conceptual understanding and analysis of the problem.

image of student response

Score Level 3 Anchor Paper

 

This response indicates application of a reasonable strategy that leads to some correct solutions. The representation in the form of an inequality has the symbol reversed (x+y≥60). The student’s graph, though missing labels, is generally well-constructed with correct scales, a solid line with correct intercepts and appropriate shading. Both the cost of lunch (15.00) and the cost of dinner (45.00) are correct. The explanation supports the solution (x+y=60; 3x=y; 3(15)=45). The student also justifies the solutions (so 15·3=45 and 45+15=60). This response demonstrates a clear understanding and analysis of the problem.

image of student response

Score Level 3 Anchor Paper

 

This response indicates application of a reasonable strategy that leads to some correct solutions. The representation in the form of an inequality is correct (x+y≤$60). The student provides a generally well-constructed graph with correct scales and a solid line with correct intercepts; however, it is not shaded to indicate the inequality. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. The explanation supports the solution (First I divided $60 by 4 which equal 15. Then I multiplied $15 times 3 because Ichiro spent 3 times as much on dinner). This response demonstrates a clear understanding and analysis of the problem.

image of student response

Score Level 4 Anchor Paper

 

This response indicates application of a reasonable strategy that leads to a correct solution within the context of the problem. The representation in the form of an inequality is correct (x+y≤60). The student provides a well-constructed graph of the inequality with correct labels, scales, a solid line with correct intercepts and appropriate shading. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. The explanation is clearly presented (I observed the “x” values of 0-20 because they are the only numbers that, multiplied by 3 are less than $60. Then I looked at each’s coresponding “y” value and 15’s was 45 which is 15 times 3). This response demonstrates a complete understanding and analysis of the problem.

image of student response

Score Level 4 Anchor Paper

 

This response indicates application of a reasonable strategy that leads to a correct solution within the context of the problem. The representation in the form of an inequality is correct (x+y≤60). The student provides a well-constructed graph of the inequality with correct labels, scales, a solid line with correct intercepts and appropriate shading. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. The explanation is fully developed (y=3x; x+3x=60; 4x=60; x=15; 15+y=60; y=45). This response demonstrates a complete understanding and analysis of the problem.

image of student response
 

Anchor Papers ~ Algebra/Data Analysis ~ Item 8

HSA 2008 Algebra/Data Analysis Item 8

CID
CID48f10ffd279ff957d2fe9be229c92a89
itemNum
8
initialLetter
itemType
ECR
itemAnswerKey
N/A
itemMaxScorePoints
4
origNum
12

Ichiro plans to spend no more than a total of $60 for both lunch and dinner each day during his vacation.

Complete the following in the Answer Book:

  • Write an inequality that models this relationship. Let x represent the amount, in dollars, that Ichiro spends on lunch. Let y represent the amount, in dollars, that Ichiro spends on dinner.
  • Graph the inequality on the grid provided in the Answer Book.
  • On Thursday, Ichiro spent exactly $60 on lunch and dinner. He spent three times as much on dinner as he spent on lunch. How much did Ichiro spend on lunch? How much did Ichiro spend on dinner? Use mathematics to explain how you determined your answers. Use words, symbols, or both in your explanations.

 

Score Level 1 Anchor Paper

 

This response indicates little application of a reasonable strategy. The representation in the form of an inequality is correct (y+x≤60). The student provides no response to the second or third parts of the question. This response demonstrates a minimal understanding and analysis of the problem.

image of student response

 

Score Level 1 Anchor Paper

 

This response indicates little application of a reasonable strategy. The representation in the form of an equation, rather than an inequality, is relevant (x+y=60). The student provides no response to the second part of the question. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. However, explanations are not provided. This response demonstrates a minimal understanding and analysis of the problem.

image of student response

 

Score Level 2 Anchor Paper

 

This response indicates application of an incomplete strategy. The representation in the form of an inequality is correct (x+y≤60). While the student assigns the axes on the grid as x and y, the inequality is not graphed. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. The explanation supports the solution (dividing 60 by 3, subtracting 5, recieving in answer of 15, multiplying 15 by 4, checking my answer to make sure it was correct. Then I multiplied 15x3 and got 45 then adding 45+15 and got $60; 45/3 is 15). This response demonstrates a conceptual understanding and analysis of the problem.

image of student response

 

Score Level 2 Anchor Paper

 

This response indicates application of an incomplete strategy. The representation in the form of an inequality is correct (x+y≤60). Although the student assigned scales and labels on the grid, the inequality is not graphed. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. The student provides a justification, rather than an explanation (I added 15 + 15 x 3 and got 60). This response demonstrates a conceptual understanding and analysis of the problem.

image of student response

 

Score Level 3 Anchor Paper

 

This response indicates application of a reasonable strategy that leads to some correct solutions. The representation in the form of an inequality has the symbol reversed (x+y≥60). The student’s graph, though missing labels, is generally well-constructed with correct scales, a solid line with correct intercepts and appropriate shading. Both the cost of lunch (15.00) and the cost of dinner (45.00) are correct. The explanation supports the solution (x+y=60; 3x=y; 3(15)=45). The student also justifies the solutions (so 15·3=45 and 45+15=60). This response demonstrates a clear understanding and analysis of the problem.

image of student response

 

Score Level 3 Anchor Paper

 

This response indicates application of a reasonable strategy that leads to some correct solutions. The representation in the form of an inequality is correct (x+y≤$60). The student provides a generally well-constructed graph with correct scales and a solid line with correct intercepts; however, it is not shaded to indicate the inequality. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. The explanation supports the solution (First I divided $60 by 4 which equal 15. Then I multiplied $15 times 3 because Ichiro spent 3 times as much on dinner). This response demonstrates a clear understanding and analysis of the problem.

image of student response

 

Score Level 4 Anchor Paper

 

This response indicates application of a reasonable strategy that leads to a correct solution within the context of the problem. The representation in the form of an inequality is correct (x+y≤60). The student provides a well-constructed graph of the inequality with correct labels, scales, a solid line with correct intercepts and appropriate shading. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. The explanation is clearly presented (I observed the “x” values of 0-20 because they are the only numbers that, multiplied by 3 are less than $60. Then I looked at each’s coresponding “y” value and 15’s was 45 which is 15 times 3). This response demonstrates a complete understanding and analysis of the problem.

image of student response

 

Score Level 4 Anchor Paper

 

This response indicates application of a reasonable strategy that leads to a correct solution within the context of the problem. The representation in the form of an inequality is correct (x+y≤60). The student provides a well-constructed graph of the inequality with correct labels, scales, a solid line with correct intercepts and appropriate shading. Both the cost of lunch ($15.00) and the cost of dinner ($45.00) are correct. The explanation is fully developed (y=3x; x+3x=60; 4x=60; x=15; 15+y=60; y=45). This response demonstrates a complete understanding and analysis of the problem.

image of student response